What is Archimedes Principle explain with example?
The principle of Archimedes is related to the energy applied to an object by the surrounding fluid. This applied energy reduces the total weight of the liquid-soaked substance. In this article, let us get acquainted with Archimedes’ system.
The principle of Archimedes states that :
The mass of the liquid displaced is.
This is because density (ρ) is defined as
Thus the weight of that displaced liquid is:
from the Archimedes principle, we can write:
The apparent loss of weight = weight of water displaced = ρ×V×g
Thus, the Thrust force is,
Archimedes Principle Examples–
1. Calculating the resulting force, if a metal ball of radius 6 cm is dipped into water.
Radius of metal ball = 6 cm = 0.06m
Volume of metal ball, V =
∴V = 9.05 × 10-4 m3
water density ρ = 1000 kg.m-3
Acceleration (due to gravity), g = 9.8 m.s-2
From Archimedes principle law we get,
Fb = ρ × g × V
Fb = (1000 kg.m-3)(9.8 m.s-2)(9.05 × 10-4 m3)
∴Fb = 8.87 N
2. Calculateing the buoyant force, if a floating object is 95% submerged into water. The density of water is 1000 kg m-3.
water density, p = 1000 kgm-3
From Archimedes principle formula,
Fb = ρ × g × V
Vb × ρb × g = ρ × g × V
ρ,g, and V are the density, acceleration due to gravity, and volume of the water
Vb , ρb , and g are the volume, density and acceleration due to gravity of body dipped
Rearranging the equation
Since, 95 percent of the body is immersed,
0.95 × Vb = V
∴ρb = 950 kgm-3